Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 593 Accepted Submission(s): 288
#include <stdio.h> #include <math.h> #include <string.h> #include <stdlib.h> #include <iostream> #include <sstream> #include <algorithm> #include <string> #include <queue> #include <vector> using namespace std; const int maxn= 1e5 + 10; const int inf = 0x3f3f3f3f; typedef long long ll; int n,m; int sum1[maxn],sum2[maxn],sum3[maxn]; int rsum1[maxn],rsum2[maxn],rsum3[maxn]; int a[maxn]; int main(int argc, char const *argv[]) { while(scanf("%d %d",&n,&m)==2) { scanf("%d",&a[1]); sum1[1]=sum2[1]=sum3[1]=a[1]; for(int i=2;i<=n;i++) { scanf("%d",&a[i]); sum1[i]=sum1[i-1] & a[i]; sum2[i]=sum2[i-1] | a[i]; sum3[i]=sum3[i-1] ^ a[i]; } rsum1[n]=rsum2[n]=rsum3[n]=a[n]; for(int i=n-1;i>=1;i--) { rsum1[i]=rsum1[i+1] & a[i]; rsum2[i]=rsum2[i+1] | a[i]; rsum3[i]=rsum3[i+1] ^ a[i]; //cout<<rsum1[i]<<" "<<rsum2[i]<<" "<<rsum3[i]<<endl; } int q; while(m--) { scanf("%d",&q); if(q==1) printf("%d %d %d\n",rsum1[2],rsum2[2],rsum3[2]); else if(q == n) printf("%d %d %d\n",sum1[n-1],sum2[n-1],sum3[n-1]); else printf("%d %d %d\n",sum1[q-1] & rsum1[q+1],sum2[q-1]|rsum2[q+1],sum3[q-1]^rsum3[q+1]); } } return 0; }
原文:http://www.cnblogs.com/stranger-/p/7476302.html