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680. Valid Palindrome II 有效的回文2

时间:2017-09-19 23:54:02      阅读:441      评论:0      收藏:0      [点我收藏+]

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome.

Example 1:

Input: "aba"
Output: True

Example 2:

Input: "abca"
Output: True
Explanation: You could delete the character ‘c‘.

Note:

  1. The string will only contain lowercase characters a-z. The maximum length of the string is 50000.
给定一个非空字符串,您最多可以删除一个字符。判断你是否可以使它成为一个回文。
  1. class Solution:
  2. def validPalindrome(self, s):
  3. """
  4. :type s: str
  5. :rtype: bool
  6. """
  7. l = 0;
  8. r = len(s) - 1
  9. while l < r:
  10. if s[l] != s[r]:
  11. s1,s2 = s[l:r],s[l+1:r+1]
  12. return (s1 == s1[::-1]) or (s2 == s2[::-1])
  13. l +=1
  14. r -=1
  15. return True





680. Valid Palindrome II 有效的回文2

原文:http://www.cnblogs.com/xiejunzhao/p/7554907.html

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