Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
For example, given candidate set 2,3,6,7 and target 7,
A solution set is: [7] [2, 2, 3]
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class Solution { public: vector<vector<int> > res; vector<int> path; vector<int> candidates; int target; void solve(int start, int sum){ if(sum > target) return; if(sum == target){ res.push_back(path); return; } for(int i = start; i < candidates.size(); ++ i){ path.push_back(candidates[i]); solve(i,sum+candidates[i]); path.pop_back(); } } vector<vector<int> > combinationSum(vector<int> &candidates, int target) { this->candidates = candidates; this->target = target; sort(this->candidates.begin(),this->candidates.end()); solve(0,0); return res; } };
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原文：http://www.cnblogs.com/xiongqiangcs/p/3809037.html