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58_Length of Last Word

时间:2017-09-30 09:41:28      阅读:273      评论:0      收藏:0      [点我收藏+]

/*

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

*/

class Solution {
public:
    int lengthOfLastWord(string s) {int ans=0,temp =0;
        for(int i=0;i<s.size();i++){
            if(s[i]!= ) temp++;
            else {
                ans = temp>0?temp:ans;
                temp = 0;}         
        }
        if(temp!=0) return ans;
        else return temp;
    }
};

 

58_Length of Last Word

原文:http://www.cnblogs.com/zhangli-ncu/p/7613548.html

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