编程题＃4：最大奇数与最小偶数之差的绝对值

#include <iostream>
using namespace std;
int main() {
    int s[6] = {0}, a = 0, b = 100;
    
// 输入6个正整数，保存在s中
    for (int i = 0; i < 6; i++)
        cin >> s[i];
    
// 求最大奇数a和最小偶数b 
    for (int i = 0; i < 6; i++) {
        if (s[i] % 2 == 1 ) {
            if (s[i] > a) 
                a = s[i];
        }
        else {
            if (s[i] < b)
                b = s[i];
        }
    }

// 求两者之差的绝对值
    int t = a - b;
    if (t < 0) t = -t;

    cout << t << endl;      
    return 0;
}