首页 > 其他 > 详细

在构造函数/析构函数中能否调用虚函数?

时间:2017-10-11 21:31:27      阅读:241      评论:0      收藏:0      [点我收藏+]
class Base
{
public:
    Base()
    {
        Fuction();
    }

    virtual void Fuction()
    {
        cout << " construct Base::Fuction" << endl;
    }

    ~Base()
    {
        desFuction();
    }

    virtual void desFuction()
    {
        cout << " destruct Base::Fuction" << endl;
    }
};

class A : public Base
{
public:
    A()
    {
        Fuction();
    }
    ~A()
    {
        desFuction();
    }
    virtual void Fuction()
    {
        cout << " construct A::Fuction" << endl;
    }
    virtual void desFuction()
    {
        cout << " destructr A::Fuction" << endl;
    }
};

int test()
{
    A a;                    
    return 0;
}

输出结果:

cout << " construct Base::Fuction" << endl;
cout << " construct A::Fuction" << endl;
cout << " destructr A::Fuction" << endl;
cout << " destruct Base::Fuction" << endl;
 

在构造函数/析构函数中能否调用虚函数?

原文:http://www.cnblogs.com/xiuxiu55/p/7652837.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!