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lintcode97- Maximum Depth of Binary Tree- easy

时间:2017-10-13 09:13:35      阅读:270      评论:0      收藏:0      [点我收藏+]

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Example

Given a binary tree as follow:

  1
 / \ 
2   3
   /   4   5

The maximum depth is 3.

 

分治法做。本层高度就是max(左高度,右高度) +1。出口是null->0。

 

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     * @param root: The root of binary tree.
     * @return: An integer.
     */
    public int maxDepth(TreeNode root) {
        // write your code here
        if (root == null){
            return 0;
        }

        int leftDepth = maxDepth(root.left) + 1;
        int rightDepth = maxDepth(root.right) + 1;

        return Math.max(leftDepth, rightDepth);
    }
}

 

lintcode97- Maximum Depth of Binary Tree- easy

原文:http://www.cnblogs.com/jasminemzy/p/7659161.html

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