Problem Description: Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Solution: 递归
1 public boolean hasPathSum(TreeNode root, int sum) { 2 if (root == null) return false; 3 if (root.left == null && root.right == null) return root.val == sum; 4 else { 5 if (root.left != null) { 6 return hasPathSum(root.left, sum - root.val) ? true : hasPathSum(root.right, sum - root.val); 7 } else { 8 return hasPathSum(root.right, sum - root.val); 9 } 10 11 } 12 }
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原文:http://www.cnblogs.com/liew/p/3813443.html