566. Reshape the Matrix
In MATLAB, there is a very useful function called ‘reshape‘, which can reshape a matrix into a new one with different size but keep its original data.
You‘re given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversingorder as they were.
If the ‘reshape‘ operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
1 Input: 2 nums = 3 [[1,2], 4 [3,4]] 5 r = 1, c = 4 6 Output: 7 [[1,2,3,4]] 8 Explanation: 9 The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.
Solution1:
1 1 //============================================================================ 2 2 // Name : Reshape the Matrix.cpp 3 3 // Author : xmh 4 4 // Version : 5 5 // Copyright : Your copyright notice 6 6 // Description : Hello World in C++, Ansi-style 7 7 //============================================================================ 8 8 9 9 #include <iostream> 10 10 #include <algorithm> 11 11 #include <vector> 12 12 using namespace std; 13 13 14 14 class Solution { 15 15 public: 16 16 vector<vector<int>> matrixReshape(vector<vector<int>>& nums, int r, int c){ 17 17 int original_r = nums.size(); 18 18 int original_c = num[0].size(); 19 19 int n = original_r * original_c; 20 20 if (n == r*c){ 21 21 vector<vector<int>> newMatrix(r, <vector<int>(c,0)); 22 22 for (int i = 0; i < n; i++) 23 23 newMatrix[i / c][i % c] = nums[i / original_c][i % original_c]; 24 24 return newMatrix; 25 25 } 26 26 else 27 27 return nums; 28 28 } 29 29 30 30 }; 31 31 32
原文：http://www.cnblogs.com/xumh/p/7694040.html