[LeetCode] Employees Earning More Than Their Managers

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+
| Employee |
+----------+
| Joe      |
+----------+

# Write your MySQL query statement below
# 1
SELECT employer.Name AS Employee FROM Employee employer JOIN Employee manager ON employer.ManagerId=manager.Id WHERE employer.Salary>manager.Salary;
# 2
SELECT employer.Name AS Employee FROM Employee employer,Employee manager WHERE employer.ManagerId=manager.Id AND employer.Salary>manager.Salary;

[LeetCode] Employees Earning More Than Their Managers

原文：http://www.cnblogs.com/immjc/p/7719480.html