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11. Container With Most Water

时间:2017-10-23 23:32:41      阅读:283      评论:0      收藏:0      [点我收藏+]
Given n non-negative integers a1, a2, ..., an, 
where each represents a point at coordinate (i, ai).
n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0).
Find two lines, which together with x-axis forms a container, such that the container contains the most water. Note: You may not slant the container.

public int maxArea(int[] height) {
        if (height == null || height.length < 2) {
            return 0;
        }
        int ans = 0;
        int l = 0, r = height.length - 1;
        while (l < r) {
            ans = Math.max(ans, Math.min(height[l], height[r]) * (r - l));
            if (height[l] < height[r]) {
                l++;
            } else {
                r--;
            }
        }
        return ans;
    }

  

11. Container With Most Water

原文:http://www.cnblogs.com/apanda009/p/7719757.html

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