Problem Description:
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get
and set
.
get(key)
- Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(key, value)
- Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
1 public static class DoubleLinkedListNode { 2 int val; 3 int key; 4 DoubleLinkedListNode pre; 5 DoubleLinkedListNode next; 6 DoubleLinkedListNode(int key, int val) {this.key = key; this.val = val;pre = null; next = null;} 7 } 8 private int capacity; 9 10 private int len; 11 private HashMap<Integer, DoubleLinkedListNode> map = 12 new HashMap<Integer, DoubleLinkedListNode>(); 13 private DoubleLinkedListNode head; 14 private DoubleLinkedListNode end; 15 public LRUCache(int capacity) { 16 this.capacity = capacity; 17 18 len = 0; 19 } 20 21 public int get(int key) { 22 23 if (map.containsKey(key)) { 24 DoubleLinkedListNode latest = map.get(key); 25 removeNode(latest); 26 setHead(latest); 27 return latest.val; 28 } else { 29 return -1; 30 } 31 32 } 33 public void removeNode(DoubleLinkedListNode node) { 34 DoubleLinkedListNode cur = node; 35 DoubleLinkedListNode pre = cur.pre; 36 DoubleLinkedListNode post = cur.next; 37 38 if (pre != null) { 39 pre.next = post; 40 } else { 41 head = post; 42 } 43 44 if (post != null) { 45 post.pre = pre; 46 } else { 47 end = pre; 48 } 49 } 50 public void setHead(DoubleLinkedListNode node) { 51 node.next = head; 52 node.pre = null; 53 if (head != null) { 54 head.pre = node; 55 } 56 57 head = node; 58 if (end == null) { 59 end = node; 60 } 61 } 62 public void set(int key, int value) { 63 64 if (map.containsKey(key)) { 65 DoubleLinkedListNode oldNode = map.get(key); 66 oldNode.val = value; 67 removeNode(oldNode); 68 setHead(oldNode); 69 } else { 70 DoubleLinkedListNode newNode = new DoubleLinkedListNode(key, value); 71 if (len < capacity) { 72 setHead(newNode); 73 map.put(key, newNode); 74 len++; 75 } else { 76 map.remove(end.key); 77 end = end.pre; 78 if (end != null) { 79 end.next = null; 80 } 81 82 setHead(newNode); 83 map.put(key, newNode); 84 } 85 } 86 87 }
Problem LRU Cache,布布扣,bubuko.com
原文:http://www.cnblogs.com/liew/p/3815014.html