Write a program to find the topological order in a digraph.
bool TopSort( LGraph Graph, Vertex TopOrder[] );
where LGraph
is defined as the following:
typedef struct AdjVNode *PtrToAdjVNode;
struct AdjVNode{
Vertex AdjV;
PtrToAdjVNode Next;
};
typedef struct Vnode{
PtrToAdjVNode FirstEdge;
} AdjList[MaxVertexNum];
typedef struct GNode *PtrToGNode;
struct GNode{
int Nv;
int Ne;
AdjList G;
};
typedef PtrToGNode LGraph;
The topological order is supposed to be stored in TopOrder[]
where TopOrder[i]
is the i
-th vertex in the resulting sequence. The topological sort cannot be successful if there is a cycle in the graph -- in that case TopSort
must return false
; otherwise return true
.
Notice that the topological order might not be unique, but the judge‘s input guarantees the uniqueness of the result.
#include <stdio.h>
#include <stdlib.h>
typedef enum {false, true} bool;
#define MaxVertexNum 10 /* maximum number of vertices */
typedef int Vertex; /* vertices are numbered from 0 to MaxVertexNum-1 */
typedef struct AdjVNode *PtrToAdjVNode;
struct AdjVNode{
Vertex AdjV;
PtrToAdjVNode Next;
};
typedef struct Vnode{
PtrToAdjVNode FirstEdge;
} AdjList[MaxVertexNum];
typedef struct GNode *PtrToGNode;
struct GNode{
int Nv;
int Ne;
AdjList G;
};
typedef PtrToGNode LGraph;
LGraph ReadG(); /* details omitted */
bool TopSort( LGraph Graph, Vertex TopOrder[] );
int main()
{
int i;
Vertex TopOrder[MaxVertexNum];
LGraph G = ReadG();
if ( TopSort(G, TopOrder)==true )
for ( i=0; i<G->Nv; i++ )
printf("%d ", TopOrder[i]);
else
printf("ERROR");
printf("\n");
return 0;
}
/* Your function will be put here */
5 7
1 0
4 3
2 1
2 0
3 2
4 1
4 2
4 3 2 1 0
5 8
0 3
1 0
4 3
2 1
2 0
3 2
4 1
4 2
ERROR
bool TopSort( LGraph Graph, Vertex TopOrder[] ) { int c = 0; int book[Graph -> Nv],h[Graph -> Nv + 1],head = 0,tail = 0; PtrToAdjVNode t; for(int i = 0;i < Graph -> Nv;i ++) book[i] = 0; for(int i = 0;i < Graph -> Nv;i ++) { t = Graph -> G[i].FirstEdge; while(t) { book[t -> AdjV] ++; t = t -> Next; } } for(int i = 0;i < Graph -> Nv;i ++) { if(book[i] == 0) { h[tail ++] = i; } } if(head == tail)return false; while(head < tail) { t = Graph -> G[h[head]].FirstEdge; while(t) { if(book[t -> AdjV] <= 0)return false; book[t -> AdjV] --; if(book[t -> AdjV] == 0)h[tail ++] = t -> AdjV; t = t -> Next; } book[h[head]] = -1; TopOrder[c ++] = h[head ++]; } if(c != Graph -> Nv)return false;///有回路 return true; }
原文:http://www.cnblogs.com/8023spz/p/7752008.html