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Copy List with Random Pointer

时间:2014-06-30 19:37:06      阅读:305      评论:0      收藏:0      [点我收藏+]

题目

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.

Return a deep copy of the list.

方法

	    public RandomListNode copyRandomList(RandomListNode head) {
	        RandomListNode newHead = null;
	        
	        if (head != null) {
	        	RandomListNode cur = head;
	        	while (cur != null) {
		        	RandomListNode temp = new RandomListNode(cur.label);
		        	temp.next = cur.next;
		        	cur.next = temp;
		        	cur = cur.next.next;
	        	}
	        	cur = head;
	        	RandomListNode newCur = head.next;
	        	while(cur != null) {
	        		if (cur.random != null) {
	        			newCur.random = cur.random.next;
	        		}
	        		cur = cur.next.next;
	        		if (cur != null) {
	        			newCur = newCur.next.next;
	        		}
	        		
	        	}
	        	
	        	cur = head;
	        	newHead = cur.next;
	        	newCur = newHead;
	        	while (cur != null) {
	        		cur.next = newCur.next;
	        		cur = newCur.next;
	        		if (cur != null) {
		        		newCur.next = cur.next;
		        		newCur = cur.next;
	        		} else {
	        			newCur.next = null;
	        		}

	        	}
	        }
	        
	        
	        return newHead;
	    }


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Copy List with Random Pointer

原文:http://blog.csdn.net/u010378705/article/details/35992867

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