c++ 函数内定义变量返回

#include<bits/stdc++.h>
using namespace std;
char * fun() {
    char s[] = "abcde";
    printf("fun:%p\n",s);
    return s;
}
char * fun1() {
    static char s[] = "abcde";
    printf("fun1:%p\n",s);
    return s;
}
char * fun2() {
    char *s = new char[6];
    strcpy(s,"abcde");
    printf("fun2:%p\n",s);
    return s;
}
int main() {
    printf("%p %s\n",fun(),fun());
    printf("%p %s\n",fun1(),fun1());
    printf("%p %s\n",fun2(),fun2());
    return 0;
}

fun:0x7ffdba452540
fun:0x7ffdba452540
(nil) (null)
fun1:0x601060
fun1:0x601060
0x601060 abcde
fun2:0x1fd3030
fun2:0x1fd3050
0x1fd3050 abcde