首页 > 其他 > 详细

21. Merge Two Sorted Lists合并两个有序链表

时间:2017-11-12 23:47:08      阅读:255      评论:0      收藏:0      [点我收藏+]

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

 不申请新的节点(把两个链表的节点接起来)

 提交通过:

 ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
        ListNode v(0),*pre = &v,*p = pre;  // pre带头结点
        while(l1 != NULL && l2 != NULL){
            if(l1->val > l2 ->val){
                p->next = l2;
                l2 = l2->next;
                p = p->next;
            }
            else{
                p->next = l1;
                l1 = l1->next;
                p = p->next;
            }
        }
        if(l1 == NULL ) p->next = l2;
        else p->next = l1;
        return pre->next;
    }

 

21. Merge Two Sorted Lists合并两个有序链表

原文:http://www.cnblogs.com/hozhangel/p/7823326.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!