函数递归

#__author__:Administrator}
#a: 2017/11/
# def jie(n):
#     if n==1:
#         return 1
#     return n*jie(n-1)
#
# print(jie(5))


#飞播那期数列：0，1，1，2，3，5，8，13，21
def fibo(n):
    befo = 0
    after = 1
    for i in range(n-2):
        sum = after+befo
        befo = after
        after = sum
    return sum

print(fibo(5))

函数递归

原文：http://www.cnblogs.com/xuxu-learn-python/p/7845408.html