HDU - 4544 湫湫系列故事――消灭兔子 2013腾讯编程马拉松复赛第三场

思路：在可以杀死兔子的箭中找最小花费的，用到了优先队列，随便复习下写法

#include <iostream>
#include <cstring>
#include <algorithm>
#include <cstdio>
#include <queue>
using namespace std;
const int MAXN = 100005;

struct Node {
	int D,P;
}node[MAXN];
int arr[MAXN], n, m;

bool cmp1(Node a, Node b) {
	return a.D < b.D;
}

struct cmp {
	bool operator() (int x, int y) {
		return x > y;
	}
};

priority_queue<int, vector<int>, greater<int> > q;

int main() {
	while (scanf("%d%d", &n, &m) != EOF) {
		while (!q.empty()) 
			q.pop();
		for (int i = 0; i < n; i++)
			scanf("%d", &arr[i]);
		for (int i = 0; i < m; i++)
			scanf("%d", &node[i].D);
		for (int i = 0; i < m; i++)
			scanf("%d", &node[i].P);
		if (n > m) {
			printf("No\n");
			continue;
		}
		sort(arr, arr+n);
		sort(node, node+m, cmp1);
		int cnt = m-1;
		int flag = 1;
		long long ans = 0;
		for (int i = n-1; i >= 0; i--) {
			while (cnt >= 0 && node[cnt].D >= arr[i]) {
				q.push(node[cnt].P);
				cnt--;
			}
			if (q.empty()) {
				flag = 0;
				break;
			}
			ans += q.top();
			q.pop();
		}
		if (flag)
			cout << ans << endl;
		else cout << "No" << endl;
	}
	return 0;
}

HDU - 4544 湫湫系列故事――消灭兔子 2013腾讯编程马拉松复赛第三场,布布扣,bubuko.com

HDU - 4544 湫湫系列故事――消灭兔子 2013腾讯编程马拉松复赛第三场

原文：http://blog.csdn.net/u011345136/article/details/36193739