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Leetcode 226: Invert Binary Tree

时间:2017-12-03 10:43:47      阅读:204      评论:0      收藏:0      [点我收藏+]

Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9

to

     4
   /     7     2
 / \   / 9   6 3   1


 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     public int val;
 5  *     public TreeNode left;
 6  *     public TreeNode right;
 7  *     public TreeNode(int x) { val = x; }
 8  * }
 9  */
10 public class Solution {
11     public TreeNode InvertTree(TreeNode root) {
12         if (root == null) return root;
13         
14         var right = root.right;
15         root.right = InvertTree(root.left);
16         root.left = InvertTree(right);
17         
18         return root;
19     }
20 }

 

Leetcode 226: Invert Binary Tree

原文:http://www.cnblogs.com/liangmou/p/7965349.html

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