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557. Reverse Words in a String III

时间:2017-12-06 13:54:31      阅读:194      评论:0      收藏:0      [点我收藏+]
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:
Input: "Let‘s take LeetCode contest"
Output: "s‘teL ekat edoCteeL tsetnoc"
Note: In the string, each word is separated by single space and there will not be any extra space in the string.

 

I just wanted to use the same logic as Reverse Words in a String II.

Step 1. Convert the string to char[] array
Step 2. Whenever I encounter a space ‘ ‘ , I call the reverse function ( just to keep the code clean )
Step 3. Repeat till the end!

Hope this helps! Thanks for voting :)

  

public String reverseWords(String s) 
{
    char[] s1 = s.toCharArray();
    int i = 0;
    for(int j = 0; j < s1.length; j++)
    {
        if(s1[j] == ‘ ‘)
        {
            reverse(s1, i, j - 1);
            i = j + 1;
        }
    }
    reverse(s1, i, s1.length - 1);
    return new String(s1);
}

public void reverse(char[] s, int l, int r)
{
	while(l < r)
	{
		char temp = s[l];
		s[l] = s[r];
		s[r] = temp;
		l++; r--;
	}
}

  

557. Reverse Words in a String III

原文:http://www.cnblogs.com/apanda009/p/7992084.html

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