898B. Proper Nutrition#买啤酒问题（枚举&取余）

#include<iostream>
using namespace std;
int main(){
    int n,a,b;
    cin>>n>>a>>b;
    if(n%2==1 && a%2==0  && b%2==0 ){cout<<"NO"<<endl;return 0;}
    if(a==b && n%a!=0){cout<<"NO"<<endl;return 0;}
    if(b%a==0 && n%a!=0){cout<<"NO"<<endl;return 0;}
    if(a%b==0 && n%b!=0){cout<<"NO"<<endl;return 0;}
    if(a==1){cout<<"YES"<<endl<<n<<" "<<0<<endl;return 0;}
    if(b==1){cout<<"YES"<<endl<<0<<" "<<n<<endl;return 0;}
    for(int i=0;i<=n/a;i++){//一层循环加上取余的方法 
        if( (n-i*a)%b==0 ){cout<<"YES"<<endl<<i<<" "<<(n-i*a)/b<<endl;return 0;}
    }
    cout<<"NO"<<endl;
    return 0;
}