给出按最底层叶子节点到根节点的数据,然后要求重建树,前序输出最终建的树。
都是两个基本操作解决:
1 二叉树插入操作
2 前序遍历
简单题目了。
#include <stdio.h> #include <string> #include <algorithm> #include <vector> using std::vector; using std::string; const int MAX_B = 1024; char buf[MAX_B]; int id = 0, len = 0; inline char getFromBuf() { if (id >= len) { len = fread(buf, 1, MAX_B, stdin); id = 0; } return buf[id++]; } void getStrFromBuf(string &n) { char a = getFromBuf(); while ((a == ' ' || a == '\n') && len) a = getFromBuf(); n.clear(); while ((a != ' ' && a != '\n') && len)//老是写&&,错成|| { n.push_back(a); a = getFromBuf(); } } struct Node { char alpha; Node *left, *right; explicit Node (char a = ' ') : alpha(a), left(NULL), right(NULL) {} }; Node *insertNode(Node *root, char a) { if (!root) return new Node(a); if (a < root->alpha) root->left = insertNode(root->left, a); else root->right = insertNode(root->right, a); return root; } void printTree(Node *r) { if (r) { putchar(r->alpha); printTree(r->left); printTree(r->right); } } void releaseTree(Node *r) { if (r) { releaseTree(r->left); releaseTree(r->right); delete r; r = NULL; } } int main() { string s; while (true) { getStrFromBuf(s); if (len == 0 || s == "$") break; vector<string> vstr; while (s != "*" && s != "$") { vstr.push_back(s); getStrFromBuf(s); } Node *root = NULL; for (int i = (int)vstr.size() - 1; i >= 0 ; i--) { for (int j = 0; j < (int)vstr[i].size(); j++) { root = insertNode(root, vstr[i][j]); } } printTree(root); releaseTree(root); putchar('\n'); } return 0; }
POJ 1577 Falling Leaves 二叉树题解,布布扣,bubuko.com
原文:http://blog.csdn.net/kenden23/article/details/36886529