Red and Black

6 9
....#.
.....#
......
......
......
......
......
#@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
###.###
...@...
###.###
..#.#..
..#.#..
0 0

45
59
6
13

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>

using namespace std;

char color[25][25];
int ans;
int w, h;
int x, y;
int dx[]= {1, -1, 0, 0};
int dy[]= {0, 0, 1, -1};

void dfs(int x, int y, int w, int h)
{
    ans++;
    color[x][y]='#';
    for(int i=0; i<4; i++)
    {
        x=x+dx[i];
        y=y+dy[i];
        if(x>=0 && x<h && y>=0 && y<w && color[x][y]=='.')
            dfs(x, y, w, h);
        x-=dx[i];    //要特别注意还原数据
        y-=dy[i];
    }
}

int main()
{
    while(scanf("%d%d", &w, &h)!=EOF)
    {
        if(w==0 && h==0)
            break;
        ans=0;
        memset(color, 0, sizeof(color));
        for(int i=0; i<h; i++)
        {
            scanf("%s", color[i]);
            for(int j=0; j<w; j++)
            {
                if(color[i][j]=='@')
                {
                    x=i;
                    y=j;
                    break;
                }
            }
        }
        dfs(x, y, w, h);
        cout<<ans<<endl;
    }

    return 0;
}

HDU 1312:Red and Black,布布扣,bubuko.com

HDU 1312:Red and Black

原文：http://blog.csdn.net/u013487051/article/details/37350929