python 基础 4 常用的运算符

luoji = True or True and False
print(luoji)
#先运算and ，然后在运算or，and的优先级较高

结果：
True

list1 = [1,2,3,4,5,18,32,16 ]
a = 10
b = 32
if a not in list1:
    print("correct,%s is not in %s"%(a,list1))
else:
    print("wrong,%s is not in %s"%(a,list1))
if b in list1:
    print("correct,%s is in %s" % (b, list1))
else:
    print("wrong,%s is not in %s" % (b, list1))

结果：
correct,10 is not in [1, 2, 3, 4, 5, 18, 32, 16]
correct,32 is in [1, 2, 3, 4, 5, 18, 32, 16]

#身份运算符 is    not is
a = 10
b = 32
if a is b:
    print("correct,%s is  %s"%(a,b))
if a is not b :
    print("correct,%s is not %s" % (a,b ))
a = 10
b = 10
if a is b:
    print("correct,%s is  %s"%(a,b))
if a is not b :
    print("correct,%s is not %s" % (a,b ))

结果：
correct,10 is not 32
correct,10 is  10