题目大意:Codeforces 444C DZY Loves Colors
题目大意:两种操作,1是修改区间上l到r上面德值为x,2是询问l到r区间总的修改值。
解题思路:线段树模板题。
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
using namespace std;
const int maxn = 5*1e5;
typedef long long ll;
ll s[maxn], del[maxn], mark[maxn];
void build (int u, int l, int r) {
if (l < r) {
int mid = (l + r)/2;
build(u*2, l, mid);
build(u*2+1, mid+1, r);
} else
mark[u] = l;
}
ll query (int u, int l, int r, int x, int y) {
if (y < l || x > r)
return 0;
if (x <= l && r <= y)
return s[u];
int mid = (l + r) / 2;
ll L = query(u*2, l, mid, x, y);
ll R = query(u*2+1, mid+1, r, x, y);
return L + R + max(0, min(r, y) - max(l, x) + 1) * del[u];
}
void clear (int u, int l, int r, int z) {
if (mark[u]) {
del[u] += abs(mark[u]-z);
s[u] += 1LL * (r-l+1) * abs(mark[u]-z);
mark[u] = 0;
} else {
if (l == r)
return;
int mid = (l + r) / 2, lc = u*2, rc = u*2+1;
clear(lc, l, mid, z);
clear(rc, mid+1, r, z);
s[u] = s[lc] + s[rc] + 1LL * (r-l+1) * del[u];
}
}
void modify (int u, int l, int r, int x, int y, int z) {
// printf("%d %d %d %d %d %d\n", u, l, r, x, y, z);
if (y < l || x > r)
return;
if (x <= l && r <= y) {
clear(u, l, r, z);
mark[u] = z;
return;
}
int mid = (l + r) / 2, lc = u*2, rc = u*2+1;
if (mark[u]) {
mark[lc] = mark[rc] = mark[u];
mark[u] = 0;
}
modify(lc, l, mid, x, y, z);
modify(rc, mid+1, r, x, y, z);
s[u] = s[lc] + s[rc] + 1LL * (r-l+1) * del[u];
}
int main () {
int n, m;
scanf("%d%d", &n, &m);
/*
memset(sum, 0, sizeof(sum));
memset(del, 0, sizeof(del));
memset(mark, 0, sizeof(mark));
*/
build(1, 1, n);
int type, x, y, z;;
for (int i = 0; i < m; i++) {
scanf("%d%d%d", &type, &x, &y);
if (type == 1) {
scanf("%d", &z);
modify(1, 1, n, x, y, z);
} else
printf("%lld\n", query(1, 1, n, x, y));
}
return 0;
}
Codeforces 444C DZY Loves Colors(线段树),布布扣,bubuko.com
Codeforces 444C DZY Loves Colors(线段树)
原文:http://blog.csdn.net/keshuai19940722/article/details/37561909