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3.6元组

时间:2018-02-07 14:23:47      阅读:229      评论:0      收藏:0      [点我收藏+]
元组
一个只读列表

a=(1,2,3,4)
print(a)
print(a[1:4])

# a[1]="4"
# print(a)   //报错

(1, 2, 3, 4)
(2, 3, 4)
Traceback (most recent call last):
File "C:/Users/xiaojiaxin/PycharmProjects/fullstack1/week1/day3/tuple1.py", line 12, in <module>
a[1]="4"
TypeError: ‘tuple‘ object does not support item assignment

Enumrate函数:

b=("a","b","c")
for i in b:
    print(i)
for i in enumerate(b):     //把索引值加进去
    print(i)
for i in enumerate(b,1):    #每个引索号+1
    print(i)
for i,v in enumerate(b,1):
    print(i,">>>>",v)
for a,c in enumerate(b,2):    #每个索引号+2
    print(a,"---",c)

a
b
c
(0, ‘a‘)
(1, ‘b‘)
(2, ‘c‘)
(1, ‘a‘)
(2, ‘b‘)
(3, ‘c‘)
1 >>>> a
2 >>>> b
3 >>>> c
2 --- a
3 --- b
4 --- c

3.6元组

原文:http://blog.51cto.com/10777193/2069808

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