Oracle 切割字符查询

select *
  from view_psbaseinfo
 where DECODE(‘410782001125,411100000043‘,
              ‘‘,
              NULL,
              ‘410782001125,411100000043‘) IS NULL
    or PSCODE in
       (SELECT REGEXP_SUBSTR(‘410782001125,411100000043‘, ‘[^,]+‘, 1, LEVEL) AS PSCODE
          FROM DUAL
        CONNECT BY LEVEL <=
                   LENGTH(‘410782001125,411100000043‘) + 1 -
                   LENGTH(REPLACE(‘410782001125,411100000043‘, ‘,‘, ‘‘)));