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huffman编码——原理与实现

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哈夫曼算法原理


Wikipedia上面说的非常清楚了,这里我就不再赘述,直接贴过来了。


1952年, David A. Huffman提出了一个不同的算法,这个算法能够为不论什么的可能性提供出一个理想的树。香农-范诺编码(Shanno-Fano)是从树的根节点到叶子节点所进行的的编码,哈夫曼编码算法却是从相反的方向,暨从叶子节点到根节点的方向编码的。

  1. 为每一个符号建立一个叶子节点,并加上其对应的发生频率
  2. 当有一个以上的节点存在时,进行下列循环:
    1. 把这些节点作为带权值的二叉树的根节点,左右子树为空
    2. 选择两棵根结点权值最小的树作为左右子树构造一棵新的二叉树,且至新的二叉树的根结点的权值为其左右子树上根结点的权值之和。
    3. 把权值最小的两个根节点移除
    4. 将新的二叉树添?队列中.
  3. 最后剩下的节点暨为根节点,此时二叉树已经完毕。

演示样例


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Huffman Algorithm
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符号 A B C D E
计数 15 7 6 6 5
概率 0.38461538 0.17948718 0.15384615 0.15384615 0.12820513

在这样的情况下,D,E的最低频率和分配分别为0和1,分组结合概率的0.28205128。如今最低的一双是B和C,所以他们就分配0和1组合结合概率的0.33333333在一起。这使得BC和DE所以0和1的前面加上他们的代码和它们结合的概率最低。然后离开仅仅是一个和BCDE,当中有前缀分别为0和1,然后结合。这使我们与一个单一的节点,我们的算法是完整的。


可得A代码的代码长度是1比特,其余字符是3比特。

字符 A B C D E
代码 0 100 101 110 111

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Pseudo-code


 1:  begin
 2:     count frequencies of single characters (source units)
 3:     output(frequencies using Fibonacci Codes of degree 2)
 4:     sort them to non-decreasing sequence
 5:     create a leaf node (character, frequency c, left son = NULL, right son = NULL) 
 6:  	   of the tree for each character and put nodes into queue F
 7:     while (|F|>=2) do 
 8:      begin
 9:        pop the first two nodes (u1, u2) with the lowest 
10:  	      frequencies from sorted queue
11:        create a node evaluated with sum of the chosen units, 
12:  	      successors are chosen units (eps, c(u1)+c(u2), u1, u2)
13:        insert new node into queue
14:      end
15:     node evaluate with way from root to leaf node (left son 1, right son 0)
16:     create output from coded intput characters
17:  end




哈夫曼算法实现



实现的时候我们用vector<bool>记录每一个char的编码;用map<char,vector<bool>>表示整个字典;
就得到了以下的代码(以下有两个,一对一错):

先放出来这个错的,以示警戒

/************************************************************************/
/*	File Name: Huffman.cpp
*		@Function: Lossless Compression
		@Author: Sophia Zhang
		@Create Time: 2012-9-26 10:40
		@Last Modify: 2012-9-26 11:10
*/
/************************************************************************/

#include"iostream"
#include "queue"
#include "map"
#include "string"
#include "iterator"
#include "vector"
#include "algorithm"
using namespace std;

#define NChar 8	//suppose use at most 8 bits to describe all symbols
#define Nsymbols 1<<NChar	//can describe 256 symbols totally (include a-z, A-Z)
typedef vector<bool> Huff_code;//8 bit code of one char
map<char,Huff_code> Huff_Dic;	//huffman coding dictionary

class HTree
{
public :
	HTree* left;
	HTree* right;
	char ch;
	int weight;

	HTree(){left = right = NULL; weight=0;}
	HTree(HTree* l,HTree* r,int w,char c){left = l;	right = r;	weight=w;	ch=c;}
	~HTree(){delete left; delete right;}
	int Getweight(){return weight?weight:left->weight+right->weight;}
	bool Isleaf(){return !left && !right; }
	bool operator < (const HTree tr) const
	{
		return tr.weight < weight;
	}
};

HTree* BuildTree(int *frequency)
{
	priority_queue<HTree*> QTree;

	//1st level add characters
	for (int i=0;i<Nsymbols;i++)
	{
		if(frequency[i])
			QTree.push(new HTree(NULL,NULL,frequency[i],(char)i));			
	}

	//build
	while (QTree.size()>1)
	{
		HTree* lc  = QTree.top();
		QTree.pop();
		HTree* rc = QTree.top();
		QTree.pop();

		HTree* parent = new HTree(lc,rc,parent->Getweight(),(char)256);
		QTree.push(parent);
	}
	//return tree root
	return QTree.top();
}

void Huffman_Coding(HTree* root, Huff_code& curcode)
{
	if(root->Isleaf())
	{
		Huff_Dic[root->ch] = curcode;
		return;
	}
	Huff_code& lcode = curcode;
	Huff_code& rcode = curcode;
	lcode.push_back(false);
	rcode.push_back(true);

	Huffman_Coding(root->left,lcode);
	Huffman_Coding(root->right,rcode);
}

int main()
{
	int freq[Nsymbols] = {0};
	char *str = "this is the string need to be compressed";

	//statistic character frequency
	while (*str!=‘\0‘)
		freq[*str++]++;

	//build tree
	HTree* r = BuildTree(freq);
	Huff_code nullcode;
	nullcode.clear();
	Huffman_Coding(r,nullcode);

	for(map<char,Huff_code>::iterator it = Huff_Dic.begin(); it != Huff_Dic.end(); it++)
	{
		cout<<(*it).first<<‘\t‘;
		Huff_code vec_code = (*it).second;
		for (vector<bool>::iterator vit = vec_code.begin(); vit!=vec_code.end();vit++)
		{
			cout<<(*vit)<<endl;
		}
	}
}


上面这段代码,我执行出来不正确。在调试的时候发现了一个问题,就是QTree优先队列中的排序出了问题,说来也是,上面的代码中,我重载小于号是对HTree object做的;而实际上我建树时用的是指针,那么优先级队列中元素为指针时该怎么办呢?

那我们将friend bool operator >(Node node1,Node node2)改动为friend bool operator >(Node* node1,Node* node2),也就是传递的是Node的指针行不行呢?


答案是不能够,由于依据c++primer中重载操作符中讲的“程序猿仅仅能为类类型或枚举类型的操作数定义重载操作符,在把操作符声明为类的成员时,至少有一个类或枚举类型的參数依照值或者引用的方式传递”,也就是说friend bool operator >(Node* node1,Node* node2)形參中都是指针类型的是不能够的。我们仅仅能再建一个类,用当中的重载()操作符作为优先队列的比較函数。




就得到了以下正确的代码:


/************************************************************************/
/*	File Name: Huffman.cpp
*		@Function: Lossless Compression
		@Author: Sophia Zhang
		@Create Time: 2012-9-26 10:40
		@Last Modify: 2012-9-26 12:10
*/
/************************************************************************/

#include"iostream"
#include "queue"
#include "map"
#include "string"
#include "iterator"
#include "vector"
#include "algorithm"
using namespace std;

#define NChar 8	//suppose use 8 bits to describe all symbols
#define Nsymbols 1<<NChar	//can describe 256 symbols totally (include a-z, A-Z)
typedef vector<bool> Huff_code;//8 bit code of one char
map<char,Huff_code> Huff_Dic;	//huffman coding dictionary

/************************************************************************/
/* Tree Class elements:
*2 child trees
*character and frequency of current node
*/
/************************************************************************/
class HTree
{
public :
	HTree* left;
	HTree* right;
	char ch;
	int weight;

	HTree(){left = right = NULL; weight=0;ch =‘\0‘;}
	HTree(HTree* l,HTree* r,int w,char c){left = l;	right = r;	weight=w;	ch=c;}
	~HTree(){delete left; delete right;}
	bool Isleaf(){return !left && !right; }
};

/************************************************************************/
/* prepare for pointer sorting*/
/*because we cannot use overloading in class HTree directly*/
/************************************************************************/
class Compare_tree
{
public:
	bool operator () (HTree* t1, HTree* t2)
	{
		return t1->weight> t2->weight;
	}
};

/************************************************************************/
/* use priority queue to build huffman tree*/
/************************************************************************/
HTree* BuildTree(int *frequency)
{
	priority_queue<HTree*,vector<HTree*>,Compare_tree> QTree;

	//1st level add characters
	for (int i=0;i<Nsymbols;i++)
	{
		if(frequency[i])
			QTree.push(new HTree(NULL,NULL,frequency[i],(char)i));			
	}

	//build
	while (QTree.size()>1)
	{
		HTree* lc  = QTree.top();
		QTree.pop();
		HTree* rc = QTree.top();
		QTree.pop();

		HTree* parent = new HTree(lc,rc,lc->weight+rc->weight,(char)256);
		QTree.push(parent);
	}
	//return tree root
	return QTree.top();
}

/************************************************************************/
/* Give Huffman Coding to the Huffman Tree*/
/************************************************************************/
void Huffman_Coding(HTree* root, Huff_code& curcode)
{
	if(root->Isleaf())
	{
		Huff_Dic[root->ch] = curcode;
		return;
	}
	Huff_code lcode = curcode;
	Huff_code rcode = curcode;
	lcode.push_back(false);
	rcode.push_back(true);

	Huffman_Coding(root->left,lcode);
	Huffman_Coding(root->right,rcode);
}

int main()
{
	int freq[Nsymbols] = {0};
	char *str = "this is the string need to be compressed";

	//statistic character frequency
	while (*str!=‘\0‘)
		freq[*str++]++;

	//build tree
	HTree* r = BuildTree(freq);
	Huff_code nullcode;
	nullcode.clear();
	Huffman_Coding(r,nullcode);

	for(map<char,Huff_code>::iterator it = Huff_Dic.begin(); it != Huff_Dic.end(); it++)
	{
		cout<<(*it).first<<‘\t‘;
		std::copy(it->second.begin(),it->second.end(),std::ostream_iterator<bool>(cout));
		cout<<endl;
	}
}




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Reference:






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huffman编码——原理与实现,布布扣,bubuko.com

huffman编码——原理与实现

原文:http://www.cnblogs.com/hrhguanli/p/3836103.html

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