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283. Move Zeroes

时间:2018-03-07 10:21:47      阅读:182      评论:0      收藏:0      [点我收藏+]

 Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

  1. You must do this in-place without making a copy of the array.
  2. Minimize the total number of operations.

 

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.

思路: 使用一个索引,指向将要替换数字的位置, 若值非空,则将该值赋值到索引所在的位置,并将索引往后移位。
class Solution {
public:
    void moveZeroes(vector<int>& nums) {
     
    int j=0;
    for(int val:nums)
    {
       if(val!=0)
          nums[j++]=val;
    }
    for(;i<nums.size();j++)
       nums[j]=0;
    }
};

 

283. Move Zeroes

原文:https://www.cnblogs.com/zhaoyaxing/p/8520303.html

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