简单DFS
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#include <cstdio> bool
used[21]; bool
prim[41]; int now[21]; int i,j,n; void
out() { printf ( "1" ); for ( int
i=2;i<=n;i++) printf ( " %d" ,now[i]); printf ( "\n" ); } void
dfs( int
step) { if
(step==n&&prim[now[n]+1]) out(); //注意是==,=导致WA for ( int
i=2;i<=n;i++) if
((!used[i])&&(prim[i+now[step]])) { used[i]= true ; now[step+1]=i; dfs(step+1); used[i]= false ; } } int
main() { int
cnt=1; for
( int i=2;i<21;i++)used[i]= false ; for
( int i=1;i<41;i++)prim[i]= true ; for ( int
i=2;i<41;i++) { if (!prim[i]) continue ; for ( int
j=2*i; j<41; j+=i)prim[j]= false ; } now[1]=1; used[1]= true ; while ( scanf ( "%d" ,&n)!=EOF) { printf ( "Case %d:\n" ,cnt++); dfs(1); puts ( "" ); } } |
原文:http://www.cnblogs.com/forever97/p/3542418.html