Path Sum

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

              5
             /             4   8
           /   /           11  13  4
         /  \              7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public boolean hasPathSum(TreeNode root, int sum) {
        return pathSum(root,sum,0);
    }
    public boolean pathSum(TreeNode node,int sum,int path){
        if(node==null) return false;
        if((node.val+path)==sum && node.left==null && node.right==null) return true;
        else return pathSum(node.left,sum,node.val+path)||pathSum(node.right,sum,node.val+path);
    }
}

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Path Sum

原文：http://blog.csdn.net/dutsoft/article/details/37737637