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283. Move Zeroes

时间:2018-04-11 10:23:29      阅读:197      评论:0      收藏:0      [点我收藏+]

Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

  1. You must do this in-place without making a copy of the array.
  2. Minimize the total number of operations.

 

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.

解题思路:

对一个vector扫一遍如果是0就删除并加一个计数器最后加上去就好了

class Solution {
public:
void moveZeroes(vector<int>& nums) {
if(nums.size()==0) return;
int count_zero=0;

for(vector<int>::iterator iter = nums.begin();iter!=nums.end();){

if(*iter == 0){

iter = nums.erase(iter);
count_zero++;
}
else{
iter++;
}

}
for(int i=0;i<count_zero;i++)
nums.push_back(0);

}
};

283. Move Zeroes

原文:https://www.cnblogs.com/liangyc/p/8793652.html

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