今日头条实习生面试常见题目 堆排序topk, 反转链表

用堆排序找出list中第K小的数字, 用小顶堆

def min_heap_k(nums, topk):
    def siftdown(nums, e, begin, end):
        i = begin
        j = 2*i + 1
        while j < end:
            if j+1 < end and num[j+1] < nums[j]:
                j += 1
            if e < nums[j]:
                break
            nums[i] = nums[j]
            i = j
            j = 2*i + 1
        nums[i] = e
    
    end = len(nums)
    for k in range(end//2, -1, -1):
        siftdown(nums, e, k, end)
    for k in range(end-1, 0, -1):
        e = nums[k]
        topk -= 1
        if topk == 0:
            return nums[0]
        siftdown(nums, e, 0, k)


if __name__ == "__main__":
    print(min_heap_k([2, 3, 1, 5, -1, 0, -10, -9, -6], topk=4))

链表反转

今日头条实习生面试常见题目 堆排序topk, 反转链表

原文：https://www.cnblogs.com/theodoric008/p/8981846.html