Python函数化编程整理

items=[1,2,3,4,5]
def inc(x):
return x+1
list(map(inc,items))

>>> a = [i+1 for i in range(3)]
>>> list(map((lambda x:x+5),a))

>>> list(filter((lambda x:x>1),a))

>>> arr = [i+1 for i in range(4)]
>>> reduce((lambda x,y:x*y),arr)

>>> a = [i+1 for i in range(3)]
>>> a

>>> arr = list(filter((lambda x:x%2==0),[i+1 for i in range(5)]))
>>> arr