class Solution { private: int queen_num; int total; public: int totalNQueens(int n) { queen_num = n; total = 0; vector<bool> h(n, false); vector<bool> v(n, false); vector<bool> lx(n * 2 + 1, false); vector<bool> rx(n * 2 + 1, false); dfs(0, h, v, lx, rx); return total; } void dfs(int level, vector<bool> &h, vector<bool> &v, vector<bool> &lx, vector<bool> &rx) { if (level == queen_num) { total++; return; } int row = level; int col = 0; while (col < queen_num) { if (!h[row] && !v[col] && !lx[row + col] && !rx[row + queen_num - col - 1]) { h[row] = v[col] = lx[row + col] = rx[row + queen_num - col - 1] = true; dfs(level + 1, h, v, lx, rx); h[row] = v[col] = lx[row + col] = rx[row + queen_num - col - 1] = false; } col++; } } };
或许可以用状态压缩?
LeetCode N-Queens II,布布扣,bubuko.com
原文:http://www.cnblogs.com/lailailai/p/3851910.html