user WHERE USER_ID in (1008622115,1008610664,1008622031,1008610318) 第二种写法：
SELECT USER_ID,USER_NAME FROM user WHERE USER_ID in (1008622115,1008610664,1008622031,1008610318)
ORDER BY field(USER_ID, 1008622115,1008610664,1008622031,1008610318)
原文：http://blog.51cto.com/landm/2122548