剑指offer 面试28题

# -*- coding:utf-8 -*-
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
class Solution:
    def isSymmetrical(self, pRoot):
        # write code here
        return self.isSymmetricalCore(pRoot,pRoot)
    
    def isSymmetricalCore(self,pRoot1,pRoot2):
        if not pRoot1 and not pRoot2:
            return True
        if not pRoot1 or not pRoot2:
            return False
        if pRoot1.val != pRoot2.val:
            return False
        return self.isSymmetricalCore(pRoot1.left,pRoot2.right) and self.isSymmetricalCore(pRoot1.right,pRoot2.left)