首页 > 其他 > 详细

matrix kpow

时间:2018-06-24 23:04:22      阅读:172      评论:0      收藏:0      [点我收藏+]

#include<iostream>
#include<cstdio>
#include<vector>
#include<queue>
#include<map>
#include<algorithm>
#include<cstdlib>
#include<string>
#include<cstring>
#include<cmath>
#include<set>
#define de(x) cout<<#x<<" = "<<x<<endl
#define push_back pb
#define make_pair mp
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
typedef vector<int> V;
typedef queue<int> Q;
typedef priority_queue<int> BQ;
typedef priority_queue<int,vector<int>,greater<int> > SQ;
typedef set<int> S;
typedef map<int,int> M;
const int maxn=1e5+10,mod=2009;
inline ll add(ll a,ll b)
{
    a+=b;
    if (a>=mod)
        a-=mod;
    if (a<0)
        a+=mod;
    return a;
}
inline ll mul(ll a,ll b)
{
    return a*b%mod;
}
struct matrix
{
    static const int N=5;
    int mat[N][N],n,m;
    matrix(){}
    matrix(int _n,int _m,int v)
    {
        n=_n;
        m=_m;
        for (int i=0;i<n;++i)
            for (int j=0;j<m;++j)
                mat[i][j]=i==j?v:0;
    }
    matrix operator * (const matrix& a) const
    {
        matrix res(n,a.m,0);
        for (int i=0;i<n;++i)
            for (int j=0;j<a.m;++j)
                for (int k=0;k<m;++k)
                    res.mat[i][j]=add(res.mat[i][j],mul(mat[i][k],a.mat[k][j]));
        return res;
    }
    matrix operator ^ (ll b) const
    {
        matrix res(n,n,1),a=*this;
        while (b)
        {
            if (b&1)
                res=res*a;
            a=a*a;
            b>>=1;
        }
        return res;
    }
};
matrix A(3,3,0),C(3,1,0);
inline void init()
{
    A.mat[0][0]=3;
    A.mat[0][1]=2;
    A.mat[0][2]=7;
    A.mat[1][0]=1;
    A.mat[2][1]=1;
    C.mat[0][0]=5;
    C.mat[1][0]=3;
    C.mat[2][0]=1;
}
int main()
{
    std::ios::sync_with_stdio(0);
    cin.tie(0);
    int i,j,k,m,n;
    int T;
    cin>>T;
    init();
    while (T--)
    {
        cin>>n;
        matrix ans=(A^(n-2))*C;
        cout<<ans.mat[0][0]<<endl;
    }
    return 0;
}

matrix kpow

原文:https://www.cnblogs.com/orangee/p/9222022.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!