解决java中按照数字大小来排序文件

 1 File[] files = file.listFiles();
 2 if(files==null)return resultFileName;
 3 List<File> fileList = new ArrayList<File>();
 4 for (File f : files) {
 5     fileList.add(f);
 6 }
 7 
 8 Collections.sort(fileList, new Comparator<File>() {
 9     @Override
10     public int compare(File o1, File o2) {
11         if (o1.isDirectory() && o2.isFile())
12             return -1;
13         if (o1.isFile() && o2.isDirectory())
14             return 1;
15         return o2.getName().compareTo(o1.getName());
16     }
17 });
18 
19 for (File f : fileList) {
20     if(f.isDirectory()){
21         resultFileName.add(f.getPath());
22         ergodic(f,resultFileName);
23     }else
24         resultFileName.add(f.getPath());
25 }

 1 public static void main(String[] args) throws IOException {
 2         File file = new File(path);
 3         File[] files = file.listFiles();
 4         ArrayList<File> list = new ArrayList<>();
 5         for (File file2 : files) {
 6 
 7             list.add(file2);
 8         }
 9         
10         Collections.sort(list, new Comparator<File>() {
11             @Override
12             public int compare(File o1, File o2) {
13                 if (o1.isDirectory() && o2.isFile())
14                     return -1;
15                 if (o1.isFile() && o2.isDirectory())
16                     return 1;
17                 Integer f = f(o1.getName());
18                 Integer f2 = f(o2.getName());
19                 return Integer.compare(f, f2);
20             }
21         });
22         for (File file2 : list) {
23             System.out.println(file2.getName());
24         }
25 
26     }
27     
28     static Integer f(String filename) {
29         int x = filename.indexOf(".");
30         String string2 = filename.substring(0,x);
31         char[] cs = string2.toCharArray();
32         StringBuilder builder = new StringBuilder();
33         for (int i = 0; i < cs.length; i++) {
34             if(Character.isDigit(cs[i])) {
35                 builder.append(cs[i]);
36             }
37         }
38         return Integer.parseInt(builder.toString());
39     }

 1 public final class FileString implements Comparable<FileString> {
 2     private final String fileName;
 3     private final int prefix_num;
 4     Pattern number = Pattern.compile("(\\d+)\\..*");
 5 
 6     public FileString(String fileName) {
 7         this.fileName = fileName;
 8         Matcher matcher = number.matcher(fileName);
 9         if (matcher.find()) {
10             prefix_num = Integer.parseInt(matcher.group(1));
11         } else {
12             prefix_num = 0;
13         }
14     }
15 
16     @Override
17     public int compareTo(FileString o) {
18         return o.prefix_num > prefix_num ? -1 : o.prefix_num == prefix_num ? 0 : 1;
19     }
20 
21     @Override
22     public String toString() {
23         return fileName;
24     }
25 }