描述
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the
length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = "Hello World", return 5.
分析
细节实现题
1 public class LengthOfLastWord { 2 3 public static void main(String[] args) { 4 // TODO Auto-generated method stub 5 String s= "hello World"; 6 System.out.println(lengthOfLastWord(s)); 7 } 8 public static int lengthOfLastWord(String s) { 9 String[] strs =s.split(" "); 10 String res=strs[strs.length-1]; 11 if(res.equals("")) { 12 return 0; 13 } 14 15 return res.length(); 16 } 17 }
原文：https://www.cnblogs.com/ncznx/p/9261261.html