1005 Spell It Right (20)（20 point(s)）

problem

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10^100^).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345
Sample Output:

one five

tip

求位数上数字的和。

anwser

using namespace std;

string GetName(int i){
    switch(i){
        case 0: return "zero";
        case 1: return "one";
        case 2: return "two";
        case 3: return "three";
        case 4: return "four";
        case 5: return "five";
        case 6: return "six";
        case 7: return "seven";
        case 8: return "eight";
        case 9: return "nine";
    }
}

int main(){
//  freopen("test.txt", "r", stdin);
    
    string N;
    int sum = 0;
    cin>>N;
    for(int i = 0; i < N.size(); i++){
        sum += (int)N[i]-48;
    }
    if (sum == 0) {
        cout<<GetName(sum);
        return 0;
    }
//  cout<<sum;
    vector<int> di;
    while(sum > 0){
        di.push_back(sum%10);
        sum/=10;
    }
    reverse (di.begin(), di.end());
    for(size_t i = 0; i < di.size(); i++){
        if (i == 0) cout<<GetName(di[i]);
        else cout<<" " << GetName(di[i]);
    }
    return 0;
}

experience

边界条件：

• 非负数 有0的情况。

时间就是生命，应该是10分钟解决的，却花了 20分钟。

1005 Spell It Right (20)（20 point(s)）

原文：https://www.cnblogs.com/yoyo-sincerely/p/9265448.html