计算两点间的距离

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 94573    Accepted Submission(s): 36296


Problem Description

Input

Output

Sample Input

0 0 0 1
0 1 1 0

Sample Output

1.00
1.41

#include<stdio.h>
#include<math.h>
int main()
{
   float x1,y1,x2,y2,result;
   while(scanf("%f%f%f%f",&x1,&y1,&x2,&y2)!=EOF)
   {
   result=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
   printf("%.2f\n",result);
   }
   return 0;
}

HDOJ 2001 计算两点间的距离,布布扣,bubuko.com

HDOJ 2001 计算两点间的距离

原文：http://blog.csdn.net/qq_16767427/article/details/38021047