numpy
result = [
[0, 10, 20, 30, 40],
[10, 23, 33, 43, 53],
[20, 83, 23, 55, 33],
[30, 93, 44, 22, 55],
[40, 72, 33, 44, 66]
]
data = np.array(result)#把一个列表变成矩阵
print(data[:2, 1])#取矩阵的前两行的前2个数，结果是[10,23]
原文：https://www.cnblogs.com/fengzi7314/p/9450635.html