443. String Compression - LeetCode

Question

443.?String Compression

Solution

题目大意：把一个有序数组压缩，

思路：遍历数组

Java实现：

public int compress(char[] chars) {
    if (chars.length == 0) return 0;

    StringBuilder sb = new StringBuilder();
    char cur = chars[0];
    int sum = 1;
    for (int i = 1; i <= chars.length; i++) {
        if (i < chars.length && chars[i] == cur) {
            sum++;
        } else {
            sb.append(String.valueOf(cur));
            if (sum > 1) {
                sb.append(sum);
            }
            if (i < chars.length) {
                cur = chars[i];
                sum = 1;
            }
        }
    }
    char[] compressChar = sb.toString().toCharArray();
    for (int i = 0; i < compressChar.length; i++) {
        chars[i] = compressChar[i];
    }
    return sb.length();
}

443. String Compression - LeetCode

原文：https://www.cnblogs.com/okokabcd/p/9454890.html