首页 > 其他 > 详细

283. Move Zeroes

时间:2018-08-17 13:43:23      阅读:147      评论:0      收藏:0      [点我收藏+]
Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

Example:

Input: [0,1,0,3,12]
Output: [1,3,12,0,0]
Note:

You must do this in-place without making a copy of the array.
Minimize the total number of operations.

Solution: make a queu and coun the number of 0 or use two pointers clerverly(think aboun the logic)

class Solution {
    public void moveZeroes(int[] nums) {
        //two pointers, move zero to the end of the array, we surely know how many 0 we have, 
        int j = 0;
        for(int i = 0; i<nums.length; i++){
            //if there is 0 j will not inncrease,  will increase
            if(nums[i] != 0){//not 0
                nums[j] = nums[i]; // move ele[i] to ele[j]
                j++;//move to next
            }
        }
        for(int i = j; i<nums.length; i++){
            nums[i] = 0;   
        }
    }
}

283. Move Zeroes

原文:https://www.cnblogs.com/stiles/p/leetcode283.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!