输出一个数组的全排列

#-*- coding:utf-8 -*-

if __name__==‘__main__‘:
    l=[1,2,3,4,5]
    l_result=[]
    for i in l:
        s=str(i)
        temp=[]
        if len(l_result)==0:
            temp.append(s)
        else:
            for j in l_result:
                for k in range(len(j)+1):
                    temp.append(j[:k]+s+j[k:])
        l_result=temp
    for i in l_result:
        temp=[j for j in i]
        print temp,

#include <bits/stdc++.h>
using namespace std;

void print(int a[],int n)
{
    for(int i=0;i<=n;i++)
    {
        cout<<a[i]<<‘ ‘;
    }
    cout<<endl;
}

void perm(int a[], int k, int m)
{
    if (k==m)
    {
        print(a,m);
        return;
    }
    for (int i=k; i<=m; i++)
    {
        swap(a[k],a[i]);
        perm(a,k+1,m);
        swap(a[k],a[i]);
    }
}

int main(void)
{
    int n;
    cin>>n;
    int a[n];
    for(int i=0;i<n;i++)
    {
        cin>>a[i];
    }
    perm(a, 0, n-1);
    return 0;
}