Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m and n respectively.
算法思路：
剑指offer上面的原题，新数组从后往前生成。
1 public class Solution { 2 public void merge(int A[], int m, int B[], int n) { 3 if(n == 0) return; 4 int index = m + n - 1; 5 int aIndex = m - 1; 6 int bIndex = n - 1; 7 while(index >= 0 ){ 8 if(bIndex < 0 ||( aIndex >= 0 && A[aIndex] >= B[bIndex])){ 9 A[index] = A[aIndex]; 10 aIndex--; 11 }else if(aIndex < 0 || ( aIndex >= 0 && A[aIndex] < B[bIndex])){ 12 A[index] = B[bIndex]; 13 bIndex--; 14 } 15 index--; 16 } 17 } 18 }
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原文：http://www.cnblogs.com/huntfor/p/3866699.html