2018网易数据挖掘方向在线笔试题

def min_max(n,k):
    min=0
    max=0
    if k==0 or k==1:
        max=0
    elif k>1:
        if n>=2*k-1:
            max=k-1
        if n<2*k-1:
            max=n-k
    return min,max

t=int(input().strip())
list=[]
for i in range(t):
    n,k=[int(j) for j in input().strip().split(" ")]
    min,max=min_max(n,k)
    list.append(min)
    list.append(max)

for i in range(0,len(list)-1,2):
    print(‘{} {}‘.format(list[i],list[i+1]))

6
1 0
1 1
2 0
2 1
2 2
6 4


0 0
0 0
0 0
0 0
0 0
0 2

Process finished with exit code 0