=(n^3+5n)/6+1
/** \brief hdu 1290
*
* \param date 2014/7/25
* \param state AC
* \return
*
*/
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
//cout << "Hello world!" << endl;
//freopen("input.txt","r",stdin);
int n;
while(scanf("%d",&n)!=EOF)
{
cout<<(n*n*n+5*n)/6+1<<endl;
}
return 0;
}
原文:http://blog.csdn.net/greenapple_shan/article/details/38126139