Codeforces Round #223 (Div. 2) 解题报告

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstdlib>
 4 #include <cmath>
 5 #include <cstring>
 6 #include <algorithm>
 7 #include <queue>
 8 #include <stack>
 9 #include <vector>
10 #define MP(a, b) make_pair(a, b)
11 #define PB(a) push_back(a)
12 
13 using namespace std;
14 
15 typedef long long ll;
16 typedef pair<int ,int> pii;
17 typedef pair<unsigned int, unsigned int> puu;
18 typedef pair<int ,double> pid;
19 typedef pair<ll, int> pli;
20 
21 const int INF = 0x3f3f3f3f;
22 const double eps = 1e-6;
23 
24 int main()
25 {
26 //    freopen("in.txt", "r", stdin);
27 
28     int a, b, s[1111], n;
29     while(scanf("%d", &n)!=EOF){
30         for(int i=0; i<n; i++){
31             scanf("%d", &s[i]);
32         }
33         int l = 0, r = n-1;
34         a = b = 0;
35         while(l<=r){
36             if(s[l]>s[r])a+=s[l++];
37             else a+=s[r--];
38             if(l>r) break;
39             if(s[l]>s[r])b+=s[l++];
40             else b+=s[r--];
41         }
42         printf("%d %d\n", a, b);
43     }
44     return 0;
45 }

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstdlib>
 4 #include <cmath>
 5 #include <cstring>
 6 #include <algorithm>
 7 #include <queue>
 8 #include <stack>
 9 #include <vector>
10 #define MP(a, b) make_pair(a, b)
11 #define PB(a) push_back(a)
12 
13 using namespace std;
14 
15 typedef long long ll;
16 typedef pair<int ,int> pii;
17 typedef pair<unsigned int, unsigned int> puu;
18 typedef pair<int ,double> pid;
19 typedef pair<ll, int> pli;
20 
21 const int INF = 0x3f3f3f3f;
22 const double eps = 1e-6;
23 const int LEN = 100010;
24 
25 int hash[LEN];
26 
27 int main()
28 {
29 //    freopen("in.txt", "r", stdin);
30 
31     int n;
32     while(scanf("%d", &n)!=EOF){
33         memset(hash, 0, sizeof hash);
34         int ans = 0;
35         for(int i=0; i<n; i++){
36             int temp;
37             scanf("%d", &temp);
38             hash[temp]++;
39             if(hash[temp]<3)ans++;
40         }
41         int maxt;
42         for(int i=5000; i>=0; i--){
43             if(hash[i]){
44                 maxt = i;
45                 break;
46             }
47         }
48         if(hash[maxt]>=2)ans--;
49         printf("%d\n", ans);
50         int f = 1;
51         for(int i=0; i<=5000; i++){
52             if(hash[i]){
53                 if(f==1){printf("%d", i);f=0;}
54                 else printf(" %d", i);
55             }
56         }
57         for(int i=5000; i>=0; i--){
58             if(hash[i]>=2){
59                 if(i==maxt)continue;
60                 if(f==1){printf("%d", i);f=0;}
61                 else printf(" %d", i);
62             }
63         }
64         printf("\n");
65     }
66     return 0;
67 }